Miscellaneous Exercise 5(II) · Q49
Q.Find the area enclosed between the circle and the line , lying in the first quadrant.
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Start your 14-day free trial to unlock the full solution →The chord meets the circle at and , coinciding with the sector's straight edges, so $A=\frac{\pi(1)^2}{4}-\frac{1}{2}(1)(1)=\frac{\pi}{4} …
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