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Miscellaneous Exercise 5(II) · Q49

Q.Find the area enclosed between the circle x2+y2=1x^2 + y^2 = 1 and the line x+y=1x + y = 1, lying in the first quadrant.

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The chord meets the circle at (1,0)(1,0) and (0,1)(0,1), coinciding with the sector's straight edges, so $A=\frac{\pi(1)^2}{4}-\frac{1}{2}(1)(1)=\frac{\pi}{4} …

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