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Miscellaneous Exercise 5(II) · Q44

Q.Find the area of the region lying between the parabolas: y2=4xy^2 = 4x and x2=4yx^2 = 4y

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Comparing y2=4xy^2=4x with y2=4axy^2=4ax gives a=1a=1; likewise x2=4yx^2=4y gives a=1a=1. Using the derived formula A=163a2A=\frac{16}{3}a^2 with a=1a=1: A=163A=\frac{16}{3}. (Directly: curves meet at (0,0)(0,0) and (4,4)(4,4), and $A=\int_0^4\left(2\sqrt x - \f …

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