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Miscellaneous Exercise 5(II) · Q48

Q.Find the area of the region bounded by the parabola y2=xy^2 = x and the line y=xy = x in the first quadrant.

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Substituting y=xy=x into y2=xy^2=x gives x2=x⇒x(x−1)=0⇒x=0,1x^2=x \Rightarrow x(x-1)=0 \Rightarrow x=0,1. Between them, the parabola's upper branch y=xy=\sqrt x lies above the line y=xy=x (checked at x=0.25x=0.25: 0.5>0.250.5>0.25). So …

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