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EXERCISE 8.1 · Q10

Q.Find the probability of throwing at most 2 sixes in 6 throws of a single die.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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With n=6n=6 throws of a die and p=16p=\dfrac16 (getting a six), q=56q=\dfrac56, X∼B(6,16)X\sim B\left(6,\tfrac16\right) counts the number of sixes.

P(X≤2)=P(0)+P(1)+P(2)P(X\le2)=P(0)+P(1)+P(2)

=6C0(56)6+6C1(16)(56)5+6C2(16)2(56)4={}^{6}C_0\left(\dfrac56\right)^6+{}^{6}C_1\left(\dfrac16\right)\left(\dfrac56\right)^5+{}^{6}C_2\left(\dfrac16\right)^2\left(\dfrac56\right)^4 …

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