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MISCELLANEOUS EXERCISE 8 (II) · Q36

Q.A computer installation has 10 terminals. Independently, the probability that any one terminal will require attention during a week is 0.10.1. Find the probabilities that

(i) 0
(ii) 1
(iii) 2
(iv) 3 or more, terminals will require attention during the next week.
Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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With n=10n=10 terminals and p=0.1p=0.1 (needs attention in a week), q=0.9q=0.9, X∼B(10,0.1)X\sim B(10,0.1).

  1. P(X=0)=(0.9)10≈0.3487P(X=0)=(0.9)^{10}\approx0.3487.
  2. P(X=1)=10C1(0.1)(0.9)9≈0.3874P(X=1)={}^{10}C_1(0.1)(0.9)^9\approx0.3874.
  3. P(X=2)=10C2(0.1)2(0.9)8≈0.1937P(X=2)={}^{10}C_2(0.1)^2(0.9)^8\approx0.1937. …

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