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MISCELLANEOUS EXERCISE 8 (I) · Q22

Q.If the mean and variance of a binomial distribution are 18 and 12 respectively, then n=…n = \ldots (A) 3636 (B) 5454 (C) 1818 (D) 2727

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E(X)=np=18E(X)=np=18 and Var(X)=npq=12\text{Var}(X)=npq=12, so q=npqnp=1218=23q=\dfrac{npq}{np}=\dfrac{12}{18}=\dfrac23, hence p=1−23=13p=1-\dfrac23=\dfrac13. …

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