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MISCELLANEOUS EXERCISE 8 (II) · Q26

Q.If a fair coin is tossed 10 times find the probability that it shows heads

(i) 5 times
(ii) in the first four tosses and tail in last six tosses.
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A fair coin tossed 10 times: p=q=12p=q=\tfrac12.

(i) 'Shows heads 5 times' means exactly 5 heads among the 10 tosses in any order, so it uses the binomial p.m.f.: P(X=5)=10C5(12)10=2521024=63256P(X=5)={}^{10}C_5\left(\tfrac12\right)^{10}=\dfrac{252}{1024}=\dfrac{63}{256}. …

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