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Exercise 6.1 · Q8

Q.A(−2,3,4)A(-2, 3, 4), B(1,1,2)B(1, 1, 2) and C(4,−1,0)C(4, -1, 0) are three points. Find the Cartesian equations of the line AB and show that points A, B, C are collinear.

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By Theorem 6.4, the Cartesian equations of line AB through A(−2,3,4)A(-2,3,4) and B(1,1,2)B(1,1,2) use direction ratios x2−x1=1−(−2)=3x_2-x_1 = 1-(-2) = 3, y2−y1=1−3=−2y_2-y_1 = 1-3 = -2, z2−z1=2−4=−2z_2-z_1 = 2-4 = -2, giving

x+23=y−3−2=z−4−2.\frac{x+2}{3} = \frac{y-3}{-2} = \frac{z-4}{-2}.

To test whether C(4,−1,0)C(4,-1,0) is collinear with A and B, substitute C's coordinates into this equation and check whether all three resulting ratios agree:

4+23=63=2,−1−3−2=−4−2=2,0−4−2=−4−2=2.\frac{4+2}{3} = \frac{6}{3} = 2,\qquad \frac{-1-3}{-2} = \frac{-4}{-2} = 2,\qquad \frac{0-4}{-2} = \frac{-4}{-2} = 2. …

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