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Question 139 of 145

Q.A line passes through the points (6,−7,−1)(6,-7,-1) and (2,−3,1)(2,-3,1). Find the direction ratios and the direction cosines of the line. Show that the line does not pass through the origin.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2025Subjective· 3mImportance★★★★★
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Find direction ratios from the two given points, normalize for direction cosines, then check whether the origin lies on the parametrized line.

Points: (6,−7,−1)(6,-7,-1) and (2,−3,1)(2,-3,1).

Direction ratios: (2−6, −3−(−7), 1−(−1))=(−4,4,2)(2-6,\ -3-(-7),\ 1-(-1))=(-4,4,2), which simplifies (dividing by 2) to (−2,2,1)(-2,2,1).

Direction cosines: magnitude =(−2)2+22+12=4+4+1=9=3=\sqrt{(-2)^2+2^2+1^2}=\sqrt{4+4+1}=\sqrt9=3.

(−23, 23, 13)\left(\frac{-2}{3},\ \frac{2}{3},\ \frac{1}{3}\right)

Does the line pass through the origin? Parametrize the line through (6,−7,−1)(6,-7,-1) with direction (−2,2,1)(-2,2,1):

x=6−2t,y=−7+2t,z=−1+tx=6-2t,\quad y=-7+2t,\quad z=-1+t

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