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Miscellaneous Exercise 6A · Q26

Q.Find the Cartesian equations of the line which passes through points (3,−2,−5)(3, -2, -5) and (3,−2,6)(3, -2, 6).

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Direction ratios of the line through (3,−2,−5)(3,-2,-5) and (3,−2,6)(3,-2,6) are

(3−3, −2−(−2), 6−(−5))=(0,0,11).(3-3,\ -2-(-2),\ 6-(-5))=(0,0,11).

Since both the xx- and yy-direction-ratios are zero, the line is parallel to the zz-axis and keeps x=3x=3, y=−2y=-2 fixed while zz varies freely. Using the point (3,−2,−5)(3,-2,-5) and these direction ratios in the standard symmetric form (with the convention that a zero denominator means that numerator …

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