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Exercise 1.3 · Q72

Q.If A={3,5,7,9,11,12}A = \{3, 5, 7, 9, 11, 12\}, determine the truth value of: ∃x∈A\exists x \in A such that x−8=1x - 8 = 1

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✓ Free question

The statement asserts that at least one element of A={3,5,7,9,11,12}A=\{3,5,7,9,11,12\} satisfies x−8=1x-8=1, i.e. x=9x=9. Checking: 3−8=−53-8=-5, 5−8=−35-8=-3, 7−8=−17-8=-1, 9−8=19-8=1 ✓, 11−8=311-8=3, 12−8=412-8=4. Since x=9∈Ax=9\in A satisfies the equation, the existential statement is true — only one witness is needed.

✓Final answer

True (x = 9 ∈ A satisfies x − 8 = 1)

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