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Exercise 1.3 · Q74

Q.If A={3,5,7,9,11,12}A = \{3, 5, 7, 9, 11, 12\}, determine the truth value of: ∃x∈A\exists x \in A such that x2<0x^2 < 0

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✓ Free question

For any real xx, x2≥0x^2 \geq 0, so x2<0x^2<0 can never hold for any element of A (or any real number at all). Since no element of A satisfies the condition, the existential statement is false.

✓Final answer

False

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