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Miscellaneous Exercise 1 · Q177

Q.Using rules in logic, prove the following: p↔q≡∼(p∧∼q)∧∼(q∧∼p)p \leftrightarrow q \equiv \sim(p \land \sim q) \land \sim(q \land \sim p)

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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p ↔ q ≡ (p → q) ∧ (q → p) ... [Biconditional Law]

≡ (~p ∨ q) ∧ (~q ∨ p) ... [Conditional Law: a→b ≡ ~a∨b, applied to both conjuncts]

≡ ~(p ∧ ~q) ∧ ~(q ∧ ~p) ... [De Morgan's Law: ~p∨q ≡ ~(p∧~q); ~q∨p ≡ ~(q∧~p)] …

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