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Exercise 1.5 · Q129

Q.Obtain the simplest logical expression of the following and draw the corresponding switching circuit: p∨(q∧∼q)p \vee (q \wedge \sim q)

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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By the complement law, q∧∼q≡Fq \wedge \sim q \equiv F (a switch and its complement can never both be closed, so this branch never carries current).

So the expression becomes p∨(q∧∼q)≡p∨Fp \vee (q \wedge \sim q) \equiv p \vee F.

By the identity law, p∨F≡pp \vee F \equiv p. …

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