Q.Inverse of statement pattern $(p \vee q) \to (p \wedge q)$ is ________.
A) $(p \wedge q) \to (p \vee q)$
B) $\sim(p \vee q) \to (p \wedge q)$
C) $(\sim p \wedge \sim q) \to (\sim p \vee \sim q)$
D) $(\sim p \vee \sim q) \to (\sim p \wedge \sim q)$

From any conditional p → q, three related conditionals can be formed. The converse is q → p (the hypothesis and conclusion swapped). The inverse is ~p → ~q (both sides negated, order kept). The contrapositive is ~q → ~p (both sides negated AND swapped). Comparing their truth tables shows two important facts: a conditional is always logically equivalent to its own contrapositive, p → q ≡ ~q → ~p, while the converse and the inverse are equivalent to EACH OTHER, q → p ≡ ~p → ~q, but neither is, in general, equivalent to the original conditional. So 'if it rains then the match is cancelled' logically guarantees 'if the match is not cancelled then it did not rain' (its contrapositive), but does NOT by itself guarantee 'if the match is cancelled then it rained' (its converse).