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Question 160 of 177

Q.If 2tan⁡−1(cos⁡x)=tan⁡−1(2csc⁡x)2\tan^{-1}(\cos x) = \tan^{-1}(2\csc x), then find the value of xx.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2022Subjective· 3mImportance★★★★★
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Use 2tan⁡−1t=tan⁡−1(2t1−t2)2\tan^{-1}t=\tan^{-1}\left(\dfrac{2t}{1-t^2}\right) on the LHS.

2tan⁡−1(cos⁡x)=tan⁡−1(2cos⁡x1−cos⁡2x)=tan⁡−1(2cos⁡xsin⁡2x)2\tan^{-1}(\cos x) = \tan^{-1}\left(\dfrac{2\cos x}{1-\cos^2x}\right) = \tan^{-1}\left(\dfrac{2\cos x}{\sin^2x}\right)

Setting this equal to tan⁡−1(2csc⁡x)=tan⁡−1(2sin⁡x)\tan^{-1}(2\csc x) = \tan^{-1}\left(\dfrac2{\sin x}\right):

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