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Question 172 of 177

Q.In △ABC\triangle ABC if a=13a=13, b=14b=14, c=15c=15 then find the values of

(i) sec⁡A\sec A
(ii) csc⁡A2\csc \dfrac{A}{2}.
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2025Subjective· 3mImportance★★★★★
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Use the cosine rule to find cos⁡A\cos A, then the half-angle formula for sin⁡(A/2)\sin(A/2).

Given a=13, b=14, c=15a=13,\ b=14,\ c=15.

By the cosine rule:

cos⁡A=b2+c2−a22bc=142+152−1322⋅14⋅15=196+225−169420=252420=35\cos A=\frac{b^2+c^2-a^2}{2bc}=\frac{14^2+15^2-13^2}{2\cdot14\cdot15}=\frac{196+225-169}{420}=\frac{252}{420}=\frac35

(i) sec⁡A=1cos⁡A=53\sec A=\dfrac{1}{\cos A}=\dfrac53

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