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Question 161 of 177

Q.In △ABC\triangle ABC, if c2+a2−b2=acc^2+a^2-b^2=ac, then ∠B=\angle B = ________.

(a) π4\dfrac{\pi}{4}
(b) π3\dfrac{\pi}{3}
(c) π2\dfrac{\pi}{2}
(d) π6\dfrac{\pi}{6}
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2023MCQ· 2mImportance★★★★★
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Compare with the cosine rule b2=a2+c2−2accos⁡Bb^2=a^2+c^2-2ac\cos B.

By the cosine rule, b2=a2+c2−2accos⁡B⇒a2+c2−b2=2accos⁡Bb^2=a^2+c^2-2ac\cos B \Rightarrow a^2+c^2-b^2=2ac\cos B.

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