Skip to content
Question 177 of 177

Q.In △ABC\triangle ABC, if A=45°A=45°, B=60°B=60° then find the ratio of its sides.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2026Subjective· 3mImportance★★★★★
100% · 177/177 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Find CC, then apply the sine rule: a:b:c=sin⁡A:sin⁡B:sin⁡Ca:b:c=\sin A:\sin B:\sin C.

A=45°, B=60°  ⟹  C=180°−45°−60°=75°A=45°,\ B=60° \implies C=180°-45°-60°=75°.

By the sine rule: a:b:c=sin⁡A:sin⁡B:sin⁡C=sin⁡45°:sin⁡60°:sin⁡75°a:b:c=\sin A:\sin B:\sin C=\sin45°:\sin60°:\sin75°

sin⁡45°=22,sin⁡60°=32\sin45°=\frac{\sqrt2}{2},\qquad \sin60°=\frac{\sqrt3}{2}

sin⁡75°=sin⁡(45°+30°)=sin⁡45°cos⁡30°+cos⁡45°sin⁡30°=22⋅32+22⋅12=6+24\sin75°=\sin(45°+30°)=\sin45°\cos30°+\cos45°\sin30°=\frac{\sqrt2}{2}\cdot\frac{\sqrt3}{2}+\frac{\sqrt2}{2}\cdot\frac12=\frac{\sqrt6+\sqrt2}{4}

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.