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Question 167 of 177

Q.Prove that: tan⁡−1(12)+tan⁡−1(13)=π4\tan^{-1}\left(\dfrac{1}{2}\right)+\tan^{-1}\left(\dfrac{1}{3}\right)=\dfrac{\pi}{4}

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2024Subjective· 3mImportance★★★★★
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Use tan⁡−1x+tan⁡−1y=tan⁡−1x+y1−xy\tan^{-1}x+\tan^{-1}y=\tan^{-1}\dfrac{x+y}{1-xy} for xy<1xy<1.

With x=12, y=13x=\dfrac12,\ y=\dfrac13: xy=16<1xy=\dfrac16<1, so the direct formula applies.

x+y1−xy=12+131−16=5/65/6=1\dfrac{x+y}{1-xy}=\dfrac{\frac12+\frac13}{1-\frac16}=\dfrac{5/6}{5/6}=1

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