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MCQ · Q1

Q.A photocell is used to automatically switch on the street lights in the evening when the sunlight is low in intensity. Thus it has to work with visible light. The material of the cathode of the photo cell is (A) zinc (B) aluminum (C) nickel (D) potassium

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For the photocell to switch the street lights on automatically at dusk, it must respond to visible light (photon energy roughly 1.6-3.2 eV across the visible spectrum), not just to ultraviolet radiation. This requires the cathode's work function ϕ0\phi_0 to be LOW enough that hν≥ϕ0h\nu\geq\phi_0 is satisfied by visible-light photons.\n\nChecking the work functions from Table 14.1: zinc has ϕ0=3.6\phi_0=3.6 eV, nickel has ϕ0=5.0\phi_0=5.0 eV, and aluminum has ϕ0=4.3\phi_0=4.3 eV -- all of these require ultraviolet radiation (photon energies above about 3.5 eV, corresponding to wavelengths below about 350 nm) to show any photoelectric emission at all, and would NOT respond reliably to ordinary visible light. Potassium, however, has a low work function of only ϕ0=2.3\phi_0=2.3 eV, well within the energy range of visible-light photons (violet light at 400 nm carries about 3.1 eV, and even orange-red light around 550-600 nm carries 2.1-2.25 eV, close to potassium's threshold). This is exactly why alkali metals like potassium are used as the photosensitive cathode material in practical photocells meant to operate with ordinary daylight/visible-light intensity changes, such as automatic street-light switches. [!ANSWER] (D) potassium.

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