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Physics · Ch 3 — Kinetic Theory of Gases and Radiation

Kirchhoff's Law of Heat Radiation and its Theoretical Proof

3.13

Kirchhoff's Law of Heat Radiation and its Theoretical Proof

Kirchhoff's law of thermal radiation connects a body's emissive power to its absorptive power, wavelength by wavelength, for a body in thermal equilibrium. It states: at a given temperature, the ratio of a body's emissive power to its coefficient of absorption equals the emissive power of a perfect blackbody at the same temperature, for every wavelength.

Since a body's emissive power can be expressed relative to a blackbody through its emissivity ee (Section 3.12.1), Kirchhoff's law can equivalently be stated as: for a body emitting and absorbing thermal radiation in thermal equilibrium, its emissivity equals its absorptivity -- symbolically, a=ea = e, or wavelength-by-wavelength, a(λ)=e(λ)a(\lambda) = e(\lambda). In other words, a body that is a strong absorber at some wavelength is, at that same wavelength and temperature, equally strong an emitter -- and a poor absorber is equally a poor emitter.

Theoretical proof. Consider an ordinary body A and a perfect blackbody B, of identical geometric shape, placed together inside a closed enclosure. Once thermal equilibrium is reached, both A and B (and the enclosure) are at the same common temperature.

Let RR be the emissive power of body A, RBR_B the emissive power of blackbody B, and aa the coefficient of absorption of body A. If QQ is the quantity of radiant heat incident on each body (per unit time), the quantity absorbed by body A is Qa=aQQ_a = aQ. Since both A and B remain at constant (equal) temperature, each must emit exactly as much energy as it absorbs, per unit time -- otherwise its temperature would drift. Because emissive power is heat radiated per unit area per unit time, this equilibrium condition for body A gives

aQ=R...for body AaQ = R \qquad \text{...for body A}

For the perfect blackbody B, since aB=1a_B = 1 (it absorbs everything incident on it), the same equilibrium condition gives simply

Q=RB...for blackbody BQ = R_B \qquad \text{...for blackbody B}

Dividing the first equation by the second:

a=RRBa = \dfrac{R}{R_B}

But by definition (Section 3.12.1), e=R/RBe = R/R_B -- so a=ea = e, which is exactly Kirchhoff's law, now proved from the requirement that both bodies stay in thermal equilibrium. …