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Q.What will happen to the mean square speed of the molecules of a gas if the temperature of the gas increases?
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From kinetic theory, the average translational kinetic energy per molecule is (1/2) m <v^2> = (3/2) kB T, so <v^2> = 3kBT/m. Since m and kB are fixed for a given gas, <v^2> is directly proportional to the absolute temperature T. So if the temperature of a gas increases, the mean square speed of its molecules increases proportionally -- doubling the absolute temperature exactly doubles the mean square speed (though the rms speed itself only increases by a factor of sqrt(2), since v_rms = sqrt(<v^2>)). [!ANSWER] The mean square speed increases in direct proportion to the absolute temperature.
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