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Physics · Ch 3 — Kinetic Theory of Gases and Radiation

Stefan-Boltzmann Law of Radiation

3.15

Stefan-Boltzmann Law of Radiation

This section makes precise exactly how much thermal radiation a blackbody emits, as a function of its temperature.

History and statement. In 1879, Josef Stefan proposed an empirical relation, based on experimental observations, between the radiant power RR emitted per unit area by a perfect blackbody and its absolute temperature TT. Five years later, Boltzmann derived the same relation theoretically from thermodynamics -- so the result is known as the Stefan-Boltzmann law. It states: the rate of emission of radiant energy per unit area (the power radiated per unit area) of a perfect blackbody is directly proportional to the fourth power of its absolute temperature.

R∝T4⟹R=σT4R \propto T^4 \qquad \Longrightarrow \qquad R = \sigma T^4

where σ\sigma is Stefan's constant, σ=5.67×10−8\sigma = 5.67\times10^{-8} J m−2^{-2}s−1^{-1}K−4^{-4} (equivalently W m−2^{-2}K−4^{-4}), with dimensions [L0M1T−3K−4][L^0M^1T^{-3}K^{-4}].

A crucial feature of this law is that the power radiated by a perfect blackbody depends only on its temperature -- not on its colour, its material, or the nature of its surface. (This is, of course, specific to the idealised perfect blackbody; Section 3.12.1's emissivity captures how real, non-ideal surfaces fall short of this.)

If a perfect blackbody of surface area AA at temperature TT radiates for a time tt, the total energy emitted is Q=AσT4tQ = A\sigma T^4 t (used directly in Example 3.6). For an ordinary (non-blackbody) surface with emissivity ee, the energy radiated per unit area per unit time is reduced proportionally:

R=eσT4R = e\sigma T^4

(used in Example 3.7 to find an unknown filament temperature from a known emissivity and power).

Radiating into a warmer or cooler surroundings. If a perfect blackbody at temperature TT sits in surroundings at a different absolute temperature T0T_0, it simultaneously radiates energy at rate σT4\sigma T^4 per unit area and absorbs energy from the surroundings at rate σT04\sigma T_0^4 per unit area (Prevost's theory of exchange, Section 3.12). Its net loss of energy per unit area per unit time is therefore

Rnet=σ(T4−T04)R_{net} = \sigma(T^4 - T_0^4)

and for an ordinary body of emissivity ee,

Rnet=eσ(T4−T04)R_{net} = e\sigma(T^4 - T_0^4)

If instead T<T0T < T_0 (the body is cooler than its surroundings), this same expression, now negative, represents a net gain of thermal energy by the body per unit area per unit time (used in Example 3.8 to compare cooling rates of a sphere at two different temperatures against a common surrounding temperature, and in Example 3.9 to compare the total radiated powers -- and hence relative sizes -- of two blackbody stars). …