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Physics · Ch 3 — Kinetic Theory of Gases and Radiation

Mayer's Relation

3.9.1

Mayer's Relation

Setup. Consider one mole of an ideal gas enclosed in a cylinder by a light, frictionless, airtight piston, with pressure PP, volume VV and temperature TT.

Heating at constant volume. If the gas is heated so its temperature rises by dTdT while the piston is held fixed (constant volume), no work is done (the piston does not move), so all the heat supplied, dQ1dQ_1, goes entirely into raising the internal energy:

dQ1=dE=CV dTdQ_1 = dE = C_V\,dT

where CVC_V is the molar specific heat at constant volume.

Heating at constant pressure. If instead the gas is heated to the same temperature rise dTdT at constant pressure, its volume increases by some dVdV, and the piston moves outward doing work dW=P dVdW = P\,dV on the surroundings. The heat supplied in this case, dQ2dQ_2, must therefore both raise the internal energy and supply this mechanical work:

dQ2=dE+dW=CP dTdQ_2 = dE + dW = C_P\,dT

where CPC_P is the molar specific heat at constant pressure.

Combining. Since the internal energy of an ideal gas depends on temperature alone (Section 3.7), the same dE=CV dTdE = C_V\,dT applies in both cases. Substituting into the constant-pressure relation:

CP dT=CV dT+dW⟹(CP−CV) dT=P dVC_P\,dT = C_V\,dT + dW \quad\Longrightarrow\quad (C_P - C_V)\,dT = P\,dV

For one mole at constant pressure, PV=RT⇒P dV=R dTPV = RT \Rightarrow P\,dV = R\,dT, so

(CP−CV) dT=R dT⟹CP−CV=R(C_P - C_V)\,dT = R\,dT \quad\Longrightarrow\quad \boxed{C_P - C_V = R}

This is Mayer's relation. (If heat is measured in calories and work in joules, it is modified to CP−CV=R/JC_P - C_V = R/J, where JJ is the mechanical equivalent of heat -- see Example 3.3.) …