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Question 79 of 102

Q.The current in the circuit is : [figure: a 15 V battery connected across three 15 Ω resistors, all three resistors in parallel with each other and with the battery]

(a) 4 A
(b) 1 A
(c) 2 A
(d) 3 A
Puducherry TnboardTamil Nadu HSC (DGE) Board 2020MCQ· 1mImportance★★★★★
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Three equal 15 Ω15\ \Omega resistors in parallel combine to 5 Ω5\ \Omega; Ohm's law with the 15 V battery then gives a total current of 3 A.

Working

For three equal resistors R=15 ΩR=15\ \Omega in parallel:

1Req=115+115+115=315 ⇒ Req=5 Ω\dfrac1{R_{eq}}=\dfrac1{15}+\dfrac1{15}+\dfrac1{15}=\dfrac3{15}\ \Rightarrow\ R_{eq}=5\ \Omega

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