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Long Answer Questions · Q19

Q.Discuss diffraction at a grating and obtain the condition for the mmth maximum.

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Step 1. A diffraction grating has alternating transparent slits of width aa and opaque rulings of width bb, with grating element e=a+be=a+b; a plane wavefront of monochromatic light incident normally on the grating diffracts at every slit simultaneously.

Step 2. Light diffracted at angle θ\theta from one pair of 'corresponding points' on two adjacent slits (points separated by exactly the grating element a+ba+b) has path difference δ=(a+b)sin⁡θ\delta=(a+b)\sin\theta -- and because every slit in the grating is identical and equally spaced, this exact same path difference applies between every adjacent pair of slits across the whole grating simultaneously.

Step 3. A bright maximum at angle θ\theta requires all these many pairs to interfere constructively together (not just cancel in pairs, as in single-slit diffraction, but reinforce en masse across every slit), which happens when the path difference between adjacent slits equals a whole number of wavelengths: δ=mλ\delta=m\lambda, m=0,1,2,…m=0,1,2,\ldots (the order of diffraction). …

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