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Multiple choice questions · Q5

Q.If the velocity and wavelength of light in air is VaV_a and λa\lambda_a and that in water is VwV_w and λw\lambda_w, then the refractive index of water is,

(a) Vw/VaV_w/V_a
(b) Va/VwV_a/V_w
(c) λw/λa\lambda_w/\lambda_a
(d) Vaλa/(Vwλw)V_a\lambda_a/(V_w\lambda_w)
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Step 1. Refractive index of water relative to air (essentially vacuum) is n=speed in airspeed in water=VaVwn=\dfrac{\text{speed in air}}{\text{speed in water}}=\dfrac{V_a}{V_w}, directly from the definition n=c/vn=c/v.

Step 2. This can equivalently be written using wavelengths instead of speeds, since v=νλv=\nu\lambda and frequency ν\nu stays the same in both media: n=VaVw=νλaνλw=λaλwn=\dfrac{V_a}{V_w}=\dfrac{\nu\lambda_a}{\nu\lambda_w}=\dfrac{\lambda_a}{\lambda_w}. …

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