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Physics · Ch 2 — Kinematics

Circular Motion

2.11.6

Circular Motion

Uniform circular motion. When a point object moves on a circular path at constant speed, covering equal arc lengths in equal time intervals, it is said to be in uniform circular motion. Even though the speed (the magnitude of v⃗\vec v) never changes, the direction of v⃗\vec v is continuously turning — velocity is always tangent to the circle, so as the particle goes around, its velocity vector sweeps through every direction in the plane of the circle.

Centripetal acceleration. Because the velocity vector's direction is changing even though its magnitude is not, there must be an acceleration, even in uniform circular motion — it is called centripetal acceleration, and it always points toward the centre of the circle ('centripetal' literally means 'centre-seeking').

Derivation: let the particle be at position r⃗1\vec r_1 with velocity v⃗1\vec v_1, and a short time Δt\Delta t later at position r⃗2\vec r_2 with velocity v⃗2\vec v_2; for uniform circular motion ∣r⃗1∣=∣r⃗2∣=r|\vec r_1|=|\vec r_2|=r and ∣v⃗1∣=∣v⃗2∣=v|\vec v_1|=|\vec v_2|=v. In this small interval, both the position vector and the velocity vector turn through the same small angle θ\theta (since v⃗⊥r⃗\vec v\perp\vec r at every instant, whatever angle r⃗\vec r turns through, v⃗\vec v turns through the identical angle). This makes the triangle of r⃗1,r⃗2,Δr⃗\vec r_1,\vec r_2,\Delta\vec r geometrically similar to the triangle of v⃗1,v⃗2,Δv⃗\vec v_1,\vec v_2,\Delta\vec v, giving the proportion

∣Δr⃗∣r=∣Δv⃗∣v\frac{|\Delta\vec r|}{r} = \frac{|\Delta\vec v|}{v}

and, because Δv⃗\Delta\vec v points radially inward (toward the centre) in this construction,

Δv⃗=−(vr)Δr⃗\Delta\vec v = -\left(\frac{v}{r}\right)\Delta\vec r

Dividing by Δt\Delta t and taking the limit Δt→0\Delta t\to0,

a⃗=lim⁡Δt→0Δv⃗Δt=−vrlim⁡Δt→0Δr⃗Δt=−vrv⃗\vec a = \lim_{\Delta t\to0}\frac{\Delta\vec v}{\Delta t} = -\frac{v}{r}\lim_{\Delta t\to0}\frac{\Delta\vec r}{\Delta t} = -\frac{v}{r}\vec v

which has magnitude

ac=v2ra_c = \frac{v^2}{r}

and, using v=rωv=r\omega from §2.11.5, this can equally be written ac=ω2ra_c=\omega^2r. Either form is standard. The centripetal acceleration has constant magnitude throughout uniform circular motion, but its direction is constantly changing (always toward the instantaneous centre), so as a vector it is very much not constant.

Non-uniform circular motion. If the object's speed also changes as it goes around (e.g. a pendulum bob swinging in a vertical circle is faster at the bottom than near the top), the motion is non-uniform circular motion, and the particle then has both a centripetal acceleration ac=v2/ra_c=v^2/r (from the changing direction) and a tangential acceleration ata_t (from the changing speed, as derived in §2.11.5) acting simultaneously. The resultant acceleration is the vector sum of these two mutually perpendicular pieces:

aR=ac2+at2=(v2r)2+at2a_R = \sqrt{a_c^2+a_t^2} = \sqrt{\left(\frac{v^2}{r}\right)^2+a_t^2}

making an angle θ\theta with the radius vector (i.e. with aca_c) given by

tan⁡θ=atac=atv2/r\tan\theta = \frac{a_t}{a_c} = \frac{a_t}{v^2/r} …

Figure 2.49Uniform circular motion

What this figure shows. A particle moving around a circular track at constant speed, with an arrow marking the fixed 'Direction of motion' tangent to the circle at each point. …

Figure 2.50Velocity in uniform circular motion

What this figure shows. Several equal-length velocity vectors (all tangent to the circle, all the same length) drawn at different points around a circle of radius rr centred at O, showing the speed (arrow length) stays constant while the direction rotates continuously. …

Figure 2.51Centripetal acceleration

What this figure shows. Two velocity vectors v⃗1\vec v_1 and v⃗2\vec v_2 at nearby points on a circle, together with their vector difference Δv⃗\Delta\vec v constructed tail-to-tail; Δv⃗\Delta\vec v points roughly toward the centre of the circle, which is the direction of the centripetal acceleration $\vec a = \Delta\v …

Figure 2.52Geometrical relationship between position and velocity vectors

What this figure shows. Two position vectors r⃗1,r⃗2\vec r_1,\vec r_2 from the centre to nearby points on the circle and the corresponding velocity vectors v⃗1,v⃗2\vec v_1,\vec v_2 (tangent at each point), both pairs subtending the same small angle θ\theta; this similarity of triangles is what gives Δv/v=Δr/r\Delta v/v = \Delta r/r, the key step in deriving ac=v2/ra_c = v^2/r. …

Figure 2.53Resultant acceleration in non-uniform circular motion

What this figure shows. A particle on a circle with its centripetal acceleration aca_c drawn pointing toward the centre O and its tangential acceleration ata_t drawn along the tangent; their vector sum, the resultant acceleration aRa_R, is drawn at an angle θ\theta to the radius (to aca_c). …