Skip to content
Exercises · 5.8

Q.Why is adsorption always exothermic ?

Telangana TsbieTextbookSubjectiveImportance★★★★★est
23% · 8/35 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1 – Thermodynamic relation.

ΔG=ΔH−TΔS\Delta G=\Delta H-T\Delta S

For a process to occur (spontaneous adsorption), ΔG\Delta G must be negative.

Step 2 – Sign of ΔS\Delta S. When a gas is adsorbed on a solid surface, its molecules lose freedom of movement (from three-dimensional gas to being fixed on a surface). This means the randomness/disorder decreases, so ΔS<0\Delta S<0; hence −TΔS-T\Delta S is positive.

Step 3 – Deduce sign of ΔH\Delta H. For ΔG=ΔH−TΔS\Delta G=\Delta H-T\Delta S to be negative while −TΔS-T\Delta S is positive, ΔH\Delta H must be negative (and large enough). A negative ΔH\Delta H means heat is released. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.