Q.Give four examples of heterogeneous catalysis.
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Homogeneous and Heterogeneous Catalysis
Imagine you want to speed up a reaction between two gases. You could dissolve a catalyst in the same gas mixture, so everything mixes at the molecular level. That is homogeneous catalysis — the catalyst and the reactants are in the same phase (all gas, all liquid, or all solid solution). The catalyst becomes part of the reaction mixture, and every catalyst molecule can directly encounter reactant molecules.
Now picture a different scenario: you have a liquid reactant, and you drop a solid metal pellet into it. The reaction happens only on the surface of the pellet. The catalyst is in a different phase from the reactants. That is heterogeneous catalysis — the catalyst is a solid (usually), while the reactants are gases or liquids. The reaction takes place at the interface between the phases.
The key distinction is phase — not solubility, not physical state alone, but whether the catalyst and reactants form a single uniform phase.
Homogeneous Catalysis — Precise Statement
A homogeneous catalyst exists in the same phase as the reactants. In solution, this means the catalyst is dissolved in the same solvent as the reactants. In the gas phase, it means the catalyst is a gas mixed with gaseous reactants.
Example: The acid-catalysed hydrolysis of an ester. The ester (liquid) and water (liquid) react slowly. Adding a few drops of concentrated sulphuric acid (also liquid) speeds it up dramatically. The acid is dissolved in the same aqueous phase as the ester and water — all are in the liquid phase.
Why it works: Because the catalyst and reactants are intimately mixed, every catalyst molecule is available. The mechanism usually involves the catalyst forming an intermediate complex with a reactant, which then reacts further and regenerates the catalyst. The activation energy is lowered because the catalyst provides an alternative pathway.
Rate=k[catalyst][reactant]
(Often first order in catalyst, because every catalyst molecule participates directly.)
Advantages: High activity per catalyst molecule, mild conditions, often high selectivity.
Disadvantage: Separating the catalyst from the product at the end can be difficult — you have to distill or extract, which costs energy and solvent.
Heterogeneous Catalysis — Precise Statement
A heterogeneous catalyst exists in a different phase from the reactants. Most commonly, the catalyst is a solid and the reactants are gases or liquids. The reaction occurs on the surface of the solid.
Example: The Haber process for ammonia. Nitrogen and hydrogen gases are passed over a solid iron catalyst at high temperature and pressure. The catalyst is solid; the reactants are gases. The reaction happens at the iron surface.
Why it works: The solid surface has active sites — atoms or ions with unsatisfied bonds. Reactant molecules adsorb (stick) onto these sites, which weakens their internal bonds and brings them close together. After reaction, the product desorbs (leaves the surface), freeing the site for the next cycle.
Think of the solid surface as a crowded dance floor. Reactants must find an empty spot (adsorb), dance (react), and then leave (desorb) before the next pair can use the spot. The number of active sites limits the rate.
Advantages: Easy separation — just filter or let the gas flow past. The catalyst is often robust and can be reused.
Disadvantage: Only the surface atoms are active — most of the catalyst mass is wasted. The reaction can be slow if the surface gets blocked (poisoned) by impurities. …
Classic industrial examples: Haber's process (Fe), Contact process (V₂O₅), Ostwald's process (Pt) and hydrogenation of oils (Ni). …
Step 1 – Meaning. In heterogeneous catalysis the catalyst is in a different phase from the reactants (usually a solid catalyst with gaseous/liquid reactants).
Step 2 – Four standard examples.
- Manufacture of ammonia (Haber's process):
N2(g)+3H2(g)Fe(s)2NH3(g)
- Manufacture of SO3 (Contact process for H2SO4):
2SO2(g)+O2(g)V2O5(s)2SO3(g)
- Oxidation of ammonia to nitric oxide (Ostwald's process):
4NH3(g)+5O2(g)Pt(s)4NO(g)+6H2O(g)
- Hydrogenation of vegetable oils to fat (vanaspati): …
Recall the standard industrial reactions where a solid catalyst acts on gaseous/liquid reac …
- Giving a homogeneous example (e.g. acid-catalysed hydrolysis) by mistake. …
- TG EAPCET 2022Set ap-2022-07-31-AN1 markMCQQ.Which of the following statements is /are correct? A) Catalyst can change ΔrG of a reaction. B) Catalyst can change the rate of a reaction. C) Catalyst can change the activation energy of a reaction. (A) A and B only (B) A, B and C (C) B and C only (D) A and C only
›Reveal solutionSolution
A catalyst speeds up a reaction by providing an alternative path with lower activation energy, but it does not change the thermodynamic quantity ΔrG (Gibbs free energy change) — only the kinetics. So statements B and C are correct; A is false.
The core idea here is the distinction between thermodynamics and kinetics. A catalyst is a substance that increases the rate of a reaction without being consumed in the overall process. It works by offering a different reaction pathway — one with a lower activation energy barrier. But the initial and final states of the reaction (the reactants and products) are exactly the same with or without the catalyst. Since ΔrG depends only on those states, not on the path taken, a catalyst cannot alter it.
Let’s examine each statement carefully.
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Statement A: "Catalyst can change ΔrG of a reaction."
ΔrG is the Gibbs free energy change of the reaction — a state function. It depends solely on the difference in free energy between products and reactants. A catalyst does not change the reactants or products; it only changes how fast the system moves from one to the other. Therefore, ΔrG remains unchanged. This statement is false.
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Statement B: "Catalyst can change the rate of a reaction."
This is the very definition of a catalyst. By lowering the activation energy, a catalyst increases the fraction of molecules that have enough energy to react at a given temperature, thereby speeding up the reaction. This statement is true.
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Statement C: "Catalyst can change the activation energy of a reaction." …
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- TG EAPCET 2021Set eng-2021-08-06-AN1 markMCQQ.The Wilkinson catalyst is (A) [(PPh3)2RhCl2] (B) [(PPh3)3RhCl] (C) [(PPh3)RhCl3] (D) [(PPh3)4RhCl]
›Reveal solutionSolution
The Wilkinson catalyst is a well-known homogeneous catalyst used primarily for the hydrogenation of alkenes. Its chemical formula is [(PPh3)3RhCl].
The question asks to identify the correct chemical formula for the Wilkinson catalyst from the given options. This catalyst is a famous example of a homogeneous transition metal catalyst, widely used in organic synthesis, particularly for the hydrogenation of alkenes. Understanding its structure involves recognizing the central metal, its oxidation state, and the specific ligands attached to it.
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Identify the central metal: The Wilkinson catalyst is a rhodium (Rh) complex. Rhodium is a Group 9 transition metal, known for forming stable complexes that are catalytically active.
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Identify the ligands: The catalyst contains two types of ligands:
- Triphenylphosphine (PPh3): This is a bulky, neutral phosphine ligand. Phosphine ligands are crucial in many homogeneous catalysts because they can tune the electronic and steric properties of the metal center, influencing its reactivity.
- Chloride (Cl): This is an anionic ligand, typically present as Cl−.
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Determine the correct stoichiometry and oxidation state: The characteristic formula for the Wilkinson catalyst is [(PPh3)3RhCl].
- In this complex, PPh3 is a neutral ligand, and Cl has a −1 charge.
- Since the overall complex is neutral, the oxidation state of rhodium can be calculated as: x+3(0)+(−1)=0 x−1=0 x=+1
- Thus, rhodium is in the +1 oxidation state, Rh(I). This Rh(I) complex is typically square planar.
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Evaluate the given options: …
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