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Exercise · Q26

Q.Describe the structure of boron oxide, B2O3\text{B}_2\text{O}_3, and explain how it is related to boric acid on heating. Give the sequence of dehydration from orthoboric acid to metaboric acid to boron oxide.

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Boron oxide, B2O3\text{B}_2\text{O}_3, is a covalent network solid built from planar, sp2sp^2-hybridised BO3\text{BO}_3 triangular units — each boron three-coordinate, bonded to three oxygen atoms in a plane — linked together through shared, bridging oxygen atoms into an extended, disordered (glass-forming) network; this network structure is exactly why B2O3\text{B}_2\text{O}_3 is the key glass-forming component of borosilicate glass. B2O3\text{B}_2\text{O}_3 is directly related to boric acid by a stepwise thermal dehydration sequence. On first heating, orthoboric acid B(OH)3\text{B(OH)}_3 loses a molecule of water to form metaboric acid, HBO2\text{HBO}_2:\nB(OH)3→ΔHBO2+H2O\text{B(OH)}_3 \xrightarrow{\Delta} \text{HBO}_2 + \text{H}_2\text{O}\nOn further, stronger heating, metaboric acid loses a further water molecule (across two HBO2\text{HBO}_2 units) to leave boron oxide itself:\n2HBO2→ΔB2O3+H2O2\text{HBO}_2 \xrightarrow{\Delta} \text{B}_2\text{O}_3 + \text{H}_2\text{O}\nSo the full dehydration sequence runs orthoboric acid $ …

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