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Example · Example 2

Q.Estimate the RMS speed of oxygen (O2O_2, molar mass 32 g/mol32\ \text{g/mol}) molecules at 300 K300\ \text{K}. Take R=8.31 J/(mol K)R = 8.31\ \text{J/(mol\,K)}.

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✓ Free question

Given M=32 g/mol=0.032 kg/molM = 32\ \text{g/mol} = 0.032\ \text{kg/mol}, T=300 KT = 300\ \text{K}, R=8.31 J/(mol K)R = 8.31\ \text{J/(mol\,K)}.

vrms=3RTM=3×8.31×3000.032=74790.032=233,719≈483 m/sv_{rms} = \sqrt{\frac{3RT}{M}} = \sqrt{\frac{3 \times 8.31 \times 300}{0.032}} = \sqrt{\frac{7479}{0.032}} = \sqrt{233{,}719} \approx 483\ \text{m/s}

✓Final answer

Oxygen molecules at 300 K300\ \text{K} have an RMS speed of about 483 m/s483\ \text{m/s}.

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