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Numerical · Q19

Q.A vessel contains 0.5 mol0.5\ \text{mol} of helium (monatomic) gas at 27 ∘C27\,^\circ\text{C}. Find the total internal energy of the gas, using U=32nRTU = \tfrac{3}{2}nRT.

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For a monatomic gas (f=3f=3), internal energy is U=f2nRT=32nRTU = \tfrac{f}{2}nRT = \tfrac{3}{2}nRT. Given n=0.5 moln=0.5\ \text{mol}, T=27 ∘C=300 KT=27\,^\circ\text{C}=300\ \text{K}, R=8.31 J/(mol K)R=8.31\ \text{J/(mol\,K)}, …

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