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Numerical · Q16

Q.Find the RMS speed of hydrogen (H2H_2, molar mass 2 g/mol2\ \text{g/mol}) molecules at 27 ∘C27\,^\circ\text{C}. Take R=8.31 J/(mol K)R = 8.31\ \text{J/(mol\,K)}.

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✓ Free question

Given M=2 g/mol=0.002 kg/molM = 2\ \text{g/mol} = 0.002\ \text{kg/mol}, T=27 ∘C=300 KT = 27\,^\circ\text{C} = 300\ \text{K}, R=8.31 J/(mol K)R=8.31\ \text{J/(mol\,K)}.

vrms=3RTM=3×8.31×3000.002=74790.002=3,739,500≈1934 m/sv_{rms} = \sqrt{\frac{3RT}{M}} = \sqrt{\frac{3 \times 8.31 \times 300}{0.002}} = \sqrt{\frac{7479}{0.002}} = \sqrt{3{,}739{,}500} \approx 1934\ \text{m/s}

✓Final answer

Hydrogen molecules at 27 ∘C27\,^\circ\text{C} have an RMS speed of about 1.93×103 m/s1.93 \times 10^3\ \text{m/s} (1.93 km/s1.93\ \text{km/s}).

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