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Exercise · Q13

Q.State the law of equipartition of energy. Use it to explain why the molar specific heat at constant volume of a diatomic gas (52R\tfrac{5}{2}R) is greater than that of a monatomic gas (32R\tfrac{3}{2}R).

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The law of equipartition of energy states that in thermal equilibrium, a gas's total energy is shared EQUALLY among all its degrees of freedom, each contributing exactly 12kBT\tfrac{1}{2}k_BT of energy per molecule (12RT\tfrac{1}{2}RT per mole).

For a molecule with ff total degrees of freedom, the total average internal energy per mole is U=f2RTU=\tfrac{f}{2}RT, so (since Cv=dU/dTC_v=dU/dT per mole, at constant volume) Cv=f2RC_v=\tfrac{f}{2}R.

A monatomic gas has f=3f=3 (translation only), giving Cv=32RC_v=\tfrac{3}{2}R. A diatomic gas additionally has 22 rotational degrees of freedom (f=5f=5), giving Cv=52RC_v=\tfrac{5}{2}R -- larger than the monatomic value specifically because there are MORE independent ways (55 vs 33) for the gas to store energy, and equipartition assigns an equal share of 12RT\tfrac{1}{2}RT to each one. A diatomic gas therefore needs MORE heat than a monatomic gas to raise its temperature by the same amount at constant volume, since part of that extra heat goes in …

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