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Numerical · Q20

Q.For nitrogen gas (treated as a rigid diatomic molecule), find CvC_v, CpC_p, and γ=Cp/Cv\gamma = C_p/C_v using the law of equipartition of energy.

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Nitrogen is a rigid diatomic gas, so f=5f=5 (Section 9.7). By equipartition (Section 9.8),

Cv=f2R=52×8.31=20.775 J/(mol K)≈20.8 J/(mol K)C_v = \frac{f}{2}R = \frac{5}{2}\times 8.31 = 20.775\ \text{J/(mol\,K)} \approx 20.8\ \text{J/(mol\,K)}

Cp=Cv+R=20.775+8.31=29.085 J/(mol K)≈29.1 J/(mol K)C_p = C_v + R = 20.775 + 8.31 = 29.085\ \text{J/(mol\,K)} \approx 29.1\ \text{J/(mol\,K)} …

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