Q.Two forces of magnitude 5 N and 5 N act at a point, with an angle of 60∘ between them. Using the triangle law of vector addition, find the magnitude of the resultant force and the angle it makes with each of the two forces.
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Concept understanding — Vector Addition and Subtraction
Only vectors describing the SAME physical quantity may be combined by addition or subtraction — two forces can be added, but a force cannot be added to a velocity. When vectors act along the same straight line, combining them is simple: parallel vectors add their magnitudes directly, while anti-parallel (opposite-direction) vectors combine by SUBTRACTING magnitudes, with the resultant pointing in the direction of the larger vector.
When two vectors do not lie along the same line, their resultant is found using one of two equivalent geometric constructions. The triangle law states that if two vectors are represented, in order, by the two sides of a triangle, their resultant is represented by the third side, drawn from the start of the first vector to the end of the second. The parallelogram law states that if two vectors (with tails at a common point) are represented by two adjacent sides of a parallelogram, their resultant is represented by the diagonal drawn from that same point; this construction, via the Pythagoras theorem, gives the resultant's magnitude as R=P2+Q2+2PQcosθ and its direction via tanα=Qsinθ/(P+Qcosθ), where θ is the angle between the two vectors.
Both constructions confirm two key algebraic properties of vector addition: it is commutative (P+Q=Q+P) and associative ((A+B)+C=A+(B+C)), so any number of vectors can be added in any order or grouping without changing the final resultant — the basis for chaining several vectors head-to-tail to find a combined resultant.
Searches for "vector addition triangle law and parallelogram law formula" and "vector addition class 11 physics important questions" are among the most common queries in the Motion in a Plane / Mathematical Tools chapters of the NCERT-aligned CBSE Class 11 Physics curriculum, since these two constructions are foundational to nearly every JEE Main and NEET mechanics question involving vectors. The resultant-magnitude formula R=P2+Q2+2PQcosθ derived here is one of the very first formulas students are expected to apply instantly and correctly in competitive exams.
[!TLDR] Use the triangle law with A=B=5 N and θ=60∘. [!ANSWER] Resultant =53≈8.66 N, making 30∘ with each of the two 5 N forces.
Using R=A2+B2+2ABcosθ with A=B=5 N and θ=60∘: R=25+25+2(5)(5)cos60∘=50+50(0.5)=75=53≈8.66 N. Since the two forces are equal in magnitude, the resultant bisects the angle between them, so it makes an angle of 30∘ with each force — confirmed by tanα=A+BcosθBsinθ=5+5cos60∘5sin60∘=7.54.33=0.577, giving α=30∘. [!ANSWER] Resultant =53≈8.66 N, making 30∘ with each of the two 5 N forces.
Apply the law of cosines for the magnitude and the sine-rule (or the equal-magnitude bisection shortcut) for the direction.
Using R=A+B (adding magnitudes directly) instead of the law of cosines.\n- Forgetting that the resultant of two equal vectors always bisects the angle between them.
Same / Similar Concept — real previous-year questions on the same or a closely similar concept, not this exact question.
CBSE 2023Set ANNUAL1 markMCQ
Q.50 N and 60 N forces are acting in opposite directions at a point. Their resultant force is:
(a) 10 Newton
(b) 110 Newton
(c) 3000 Newton
(d) Zero
›Reveal solutionSolution
For two forces acting along the same line but in opposite directions, the resultant is the difference of their magnitudes, directed along the larger force.
When two vectors act along the same straight line, the angle between them is either 0∘ (same direction) or 180∘ (opposite direction). Using the general formula for the resultant of two vectors F1 and F2 with angle θ between them,
R=F12+F22+2F1F2cosθ
for θ=180∘, cosθ=−1, so
R=F12+F22−2F1F2=(F1−F2)2=∣F1−F2∣
Here F1=60N and F2=50N, so
R=60−50=10N
acting in the direction of the larger (60 N) force.