Skip to content
Numerical · Q22

Q.Rain is falling vertically downward at 10 m/s. A man runs horizontally at 6 m/s. Find the velocity of the rain relative to the man (magnitude and direction), and the angle from the vertical at which he should hold his umbrella.

West Bengal WbchseTextbookSubjectiveImportance★★★★★est
79% · 22/28 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Taking the man's running direction as i^\hat i (horizontal) and upward as +j^+\hat j: v⃗rain,ground=−10j^\vec v_{\text{rain,ground}} = -10\hat j m/s (falling straight down), v⃗man,ground=6i^\vec v_{\text{man,ground}} = 6\hat i m/s. Relative velocity of the rain as seen by the man: v⃗rain,man=v⃗rain,ground−v⃗man,ground=−6i^−10j^\vec v_{\text{rain,man}} = \vec v_{\text{rain,ground}} - \vec v_{\text{man,ground}} = -6\hat i - 10\hat j m/s. Magnitude: 62+102=136≈11.66\sqrt{6^2+10^2} = \sqrt{136} \approx 11.66 m/s. The angle from the vertical (the −j^-\hat j direction) is tan⁡−1(6/10)=tan⁡−1(0.6)≈30.96∘≈31∘\tan^{-1}(6/10) = \tan^{-1}(0.6) \approx 30.96^\circ \approx 31^\circ, tilted toward the −i^-\hat i direction relative to the ground rain, which — from the man's point of view — means the rain appears to come from ahead of him, tilted fo …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.