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Numerical · Q18

Q.A vector of magnitude 20 units makes an angle of 60∘60^\circ with the positive x-axis. Find its x- and y-components.

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With A=20A=20 units and θ=60∘\theta=60^\circ: Ax=20cos⁡60∘=20(0.5)=10A_x = 20\cos60^\circ = 20(0.5) = 10 units; Ay=20sin⁡60∘=20(32)=103≈17.3A_y = 20\sin60^\circ = 20\left(\dfrac{\sqrt3}{2}\right) = 10\sqrt3 \approx 17.3 units. Check: 102+(103)2=100+300=400=20\sqrt{10^2+(10\sqrt3)^2} = \sqrt{100+300} = \sqrt{400} = 20, matching the original magnitude. [!ANSWER] Ax=10A_x = 10 units and Ay=103≈17.3A_y = 10\sqrt3 \approx 17.3 units.

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