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Numerical · Q17

Q.Two vectors P⃗\vec P (6 units) and Q⃗\vec Q (8 units) act at a point at right angles to each other. Find the magnitude of the resultant and the angle it makes with P⃗\vec P.

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Since P⃗\vec P (6 units) and Q⃗\vec Q (8 units) are at right angles, R=P2+Q2=62+82=36+64=100=10R=\sqrt{P^2+Q^2}=\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10 units. Direction: tan⁡θ=Q/P=8/6=4/3≈1.333\tan\theta = Q/P = 8/6 = 4/3 \approx 1.333, so θ=tan⁡−1(4/3)≈53.13∘≈53∘\theta = \tan^{-1}(4/3) \approx 53.13^\circ \approx 53^\circ from P⃗\vec P (the standard 6-8-10 / 3-4-5-scaled triangle, complementary to the 37∘37^\circ seen earlier). [!ANSWER] Resultant magnitude = 10 units, at 53∘53^\circ to P⃗\vec P.

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