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Example · Example 3

Q.A displacement vector of magnitude 10 m makes an angle of 30∘30^\circ with the positive x-axis. Find its rectangular components AxA_x and AyA_y.

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With A=10A = 10 m and θ=30∘\theta = 30^\circ: Ax=Acos⁡θ=10cos⁡30∘=10×32=53≈8.66A_x = A\cos\theta = 10\cos30^\circ = 10 \times \dfrac{\sqrt3}{2} = 5\sqrt3 \approx 8.66 m, and Ay=Asin⁡θ=10sin⁡30∘=10×0.5=5A_y = A\sin\theta = 10\sin30^\circ = 10 \times 0.5 = 5 m. As a check, Ax2+Ay2=75+25=100=10\sqrt{A_x^2+A_y^2} = \sqrt{75+25} = \sqrt{100} = 10 m, matching the original magnitude. [!ANSWER] Ax=53≈8.66A_x = 5\sqrt3 \approx 8.66 m and Ay=5A_y = 5 m.

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