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Example · Example 6

Q.A Carnot engine takes in heat from a source at 600 K600\ \text{K} and rejects heat to a sink at 300 K300\ \text{K}. Calculate the efficiency of the engine.

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Given: source temperature T1=600 KT_1 = 600\ \text{K}, sink temperature T2=300 KT_2 = 300\ \text{K}.

The efficiency of a Carnot engine operating between these two temperatures is

ηCarnot=1−T2T1=1−300600=1−0.5=0.5\eta_{\text{Carnot}} = 1 - \frac{T_2}{T_1} = 1 - \frac{300}{600} = 1 - 0.5 = 0.5 …

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