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Exercise · Q17

Q.Arrange Cr, Mn, Fe, Co, Ni, Cu and Zn in order of increasing metallic radius, and explain why the radius rises again towards the end of the series.

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Across the middle-to-late part of the first-row transition series, metallic radius first flattens out (Cr through Ni are all within about 3 pm of one another, roughly 115115-118118 pm) and then rises noticeably by the time zinc is reached (≈125\approx 125 pm).

Comparing Cr, Mn, Fe, Co and Ni: these five sit in the "plateau" region of the trend described earlier in this chapter, where the increase in nuclear charge across each step is very nearly cancelled by the increase in electron-electron repulsion within the increasingly occupied 3d3d subshell, so their radii are all close to one another, with nickel typically the smallest of the five.

Moving on to copper and especially zinc, the radius begins to increase. By copper, the 3d3d subshell is completely filled (3d104s13d^{10}4s^1); by zinc, both the 3d103d^{10} and 4s24s^2 subshells are completely filled. In each case, adding a further electron to an already substantially or completely filled shell increases the electron-electron repulsion within that shell more sharply than any further increase in nuclear attraction can compensate for, so the outer electron cloud is pushed outward and the atom becomes measurably larger than its immediate neighbours to the left. Zinc, with the largest and most complete additional filling (4s24s^2 on top of a full 3d103d^{10}), shows this effect most strongly, giving it the largest metallic radius of any first-row transition metal.

Putting the whole sequence together, the approximate order of increasing metallic radius is: Ni<Co≈Fe<Mn<Cr<Cu<Zn\text{Ni} < \text{Co} \approx \text{Fe} < \text{Mn} < \text{Cr} < \text{Cu} < \text{Zn}.

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Approximate order of increasing metallic radius: Ni (115)<Co (116)≈Fe (116)<Mn (117)≈Cr (118)<Cu (117-119)<Zn (125 pm)\text{Ni}\ (115) < \text{Co}\ (116) \approx \text{Fe}\ (116) < \text{Mn}\ (117) \approx \text{Cr}\ (118) < \text{Cu}\ (117\text{-}119) < \text{Zn}\ (125\ \text{pm}). The rise from Ni/Cu to Zn occurs because the 3d subshell is by then completely (Zn) or nearly completely (Cu) filled, and the resulting electron-electron repulsion among the paired d electrons outweighs the (only slowly increasing) nuclear attraction, pushing the outer electron cloud outward again.

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