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Exercise · Q29

Q.Give the general electronic configuration of the actinoids, and explain why actinoids show a wider range of oxidation states than the lanthanoids.

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The fourteen actinoids, thorium (Z=90Z=90) through lawrencium (Z=103Z=103), follow actinium in the periodic table, with electrons progressively filling the 5f subshell. Their general outer configuration is

[Rn]5f1−146d0−27s2[\text{Rn}]5f^{1-14}6d^{0-2}7s^2

directly analogous in form to the lanthanoids' [Xe]4f1−145d0−16s2[\text{Xe}]4f^{1-14}5d^{0-1}6s^2, but one row lower, built on the radon core, and (as reflected in the 6d0−26d^{0-2} range, wider than the lanthanoids' 5d0−15d^{0-1}) showing even more irregular filling across the series than the lanthanoids do.

Why the oxidation-state range is wider. For the lanthanoids, the 4f orbitals lie deep within the atom, well shielded by the filled outer 5s25p65s^2 5p^6 shell that lies outside them; as a result, 4f electrons are only weakly involved in chemical bonding, and almost all lanthanoids are restricted to the single dominant +3+3 oxidation state (formed simply from the readily lost outer 6s26s^2 plus 5d0−15d^{0-1} electrons), with only the handful of +2+2/+4+4 exceptions covered in an earlier exercise. …

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