Skip to content
Exercise · Q20

Q.KMnO4\text{KMnO}_4 and K2Cr2O7\text{K}_2\text{Cr}_2\text{O}_7 are intensely coloured even though Mn7+\text{Mn}^{7+} and Cr6+\text{Cr}^{6+} have a d0d^0 configuration with no d-electrons available for a d-d transition. Explain the real source of their colour.

West Bengal WbchseTextbookSubjectiveImportance★★★★★
41% · 20/49 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

The d-d transition mechanism developed earlier in this chapter explains colour only for ions with a partially filled d subshell -- an electron already present in the metal's d orbitals is excited from a lower-energy to a higher-energy d orbital. MnO4−\text{MnO}_4^- and Cr2O72−\text{Cr}_2\text{O}_7^{2-} are genuine exceptions to any attempt to explain their colour this way, because manganese in MnO4−\text{MnO}_4^- is in the +7+7 oxidation state (having formally lost all seven of its valence electrons, 3d54s23d^54s^2) and chromium in Cr2O72−\text{Cr}_2\text{O}_7^{2-} is in the +6+6 state (having formally lost all six of its valence electrons, 3d54s13d^54s^1). Both metal centres are therefore d0d^0: there are no d electrons present at all, so a d-d transition is structurally impossible, exactly as it is for the genuinely colourless Sc3+\text{Sc}^{3+} (d0d^0) ion discussed earlier.

Yet KMnO4\text{KMnO}_4 solutions are an intense purple and K2Cr2O7\text{K}_2\text{Cr}_2\text{O}_7 solutions a strong orange -- among the most vividly coloured simple ions in inorganic chemistry. The real mechanism responsible is called charge transfer, and more specifically a ligand-to-metal charge-transfer (LMCT) transition: an electron is excited not between two orbitals both centred on the metal (as in a d-d transition), but from a filled molecular orbital that is largely centred on the surrounding oxygen ligands directly into an empty d orbital on the metal centre. Because the metal ion is highly charged and strongly electron-attracting (a d0d^0, high-oxidation-state metal centre is a particularly good electron acceptor), and because oxygen is a good electron donor, this charge-transfer transition typically requires only a modest amount of energy -- corresponding to a photon in the visible region -- and, being an intrinsically more probable ("allowed") transi …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.