Q. and are intensely coloured even though and have a configuration with no d-electrons available for a d-d transition. Explain the real source of their colour.
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Start your 14-day free trial to unlock the full solution →The d-d transition mechanism developed earlier in this chapter explains colour only for ions with a partially filled d subshell -- an electron already present in the metal's d orbitals is excited from a lower-energy to a higher-energy d orbital. and are genuine exceptions to any attempt to explain their colour this way, because manganese in is in the oxidation state (having formally lost all seven of its valence electrons, ) and chromium in is in the state (having formally lost all six of its valence electrons, ). Both metal centres are therefore : there are no d electrons present at all, so a d-d transition is structurally impossible, exactly as it is for the genuinely colourless () ion discussed earlier.
Yet solutions are an intense purple and solutions a strong orange -- among the most vividly coloured simple ions in inorganic chemistry. The real mechanism responsible is called charge transfer, and more specifically a ligand-to-metal charge-transfer (LMCT) transition: an electron is excited not between two orbitals both centred on the metal (as in a d-d transition), but from a filled molecular orbital that is largely centred on the surrounding oxygen ligands directly into an empty d orbital on the metal centre. Because the metal ion is highly charged and strongly electron-attracting (a , high-oxidation-state metal centre is a particularly good electron acceptor), and because oxygen is a good electron donor, this charge-transfer transition typically requires only a modest amount of energy -- corresponding to a photon in the visible region -- and, being an intrinsically more probable ("allowed") transi …
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