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Exercise · Q23

Q.Write the equilibrium that interconverts the chromate ion and the dichromate ion, and explain how the pH of the solution controls which species predominates.

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Chromium(VI) in aqueous solution exists as an equilibrium mixture of two interconvertible species, the chromate ion, CrO42−\text{CrO}_4^{2-} (yellow), and the dichromate ion, Cr2O72−\text{Cr}_2\text{O}_7^{2-} (orange), related by the equilibrium

2CrO42−+2H+⇌Cr2O72−+H2O2\text{CrO}_4^{2-} + 2\text{H}^+ \rightleftharpoons \text{Cr}_2\text{O}_7^{2-} + \text{H}_2\text{O}

Structurally, the dichromate ion is formed by two CrO4\text{CrO}_4 tetrahedra condensing together (sharing one corner oxygen, with loss of a water molecule), a reaction that consumes H+\text{H}^+ ions and is therefore directly sensitive to the solution's pH.

By Le Chatelier's principle, since H+\text{H}^+ appears as a reactant on the left-hand side of the equilibrium, increasing the concentration of H+\text{H}^+ (i.e. making the solution more acidic, by adding an acid) shifts the equilibrium to the right, favouring the orange dichromate ion; this is exactly why the manufacture of potassium dichromate, described earlier in this chapter, requires an explicit acidification step to convert the initially formed sodium chromate into the dichromate salt.

Conversely, decreasing the concentration of H+\text{H}^+ (i.e. making the solution more alkaline, by adding a base, which removes H+\text{H}^+ ions from solution) shifts the equilibrium to the left, favouring the yellow chromate ion -- so dissolving potassium dichromate in an alkaline solution turns the colour from orange back to yellow, a classic and easily demonstrated laboratory illustration of this equilibrium. …

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