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Question 38 of 44

Q.(a) Draw a labelled diagram of A.C. generator. [1]

(b) Obtain an expression for the instantaneous value of the emf generated in A.C. generator. [2]
(c) The primary and the secondary coils of an ideal step-down transformer consist of 600 and 25 turns respectively. When the primary coil of this transformer is connected to 240 V mains, the current in the primary coil is 15 A. Calculate —
(i) the current in the secondary coil. [1]
(ii) the average power delivered to the output circuit. [1]
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2024Subjective· 5mImportance★★★★★
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Figure — Part (a) is a hard 'Draw a labelled diagram of A.C. generator' worth 1 mark in a single (non-OR) question; the
Figure — Part (a) is a hard 'Draw a labelled diagram of A.C. generator' worth 1 mark in a single (non-OR) question; the

An AC generator produces a sinusoidal emf as a coil rotates in a magnetic field; applying the ideal-transformer turns-ratio relations to the given step-down transformer gives the secondary current and power delivered.

  1. Labelled diagram of an AC generator: An AC generator (alternator) consists of: a rectangular (or multi-turn) ARMATURE COIL free to rotate about an axis perpendicular to a uniform magnetic field B⃗\vec{B} (produced by strong field magnets/poles, N and S); the two ends of the coil are connected to two SLIP RINGS, which rotate along with the coil; two fixed carbon BRUSHES press against the slip rings and connect the rotating coil to the external circuit; and a mechanical energy source (e.g. a turbine or hand crank) that rotates the coil/armature at constant angular speed ω\omega.
  2. Expression for the instantaneous emf: As the coil (area AA, NN turns) rotates with angular velocity ω\omega in field BB, the flux linked with it at time tt (measuring the angle from the position where the coil plane is perpendicular to BB) is ϕ(t)=NBAcos⁡(ωt)\phi(t) = NBA\cos(\omega t) By Faraday's law, the induced emf is e=−dϕdt=−NBAddtcos⁡(ωt)=NBAωsin⁡(ωt)e = -\dfrac{d\phi}{dt} = -NBA\dfrac{d}{dt}\cos(\omega t) = NBA\omega\sin(\omega t) Writing e0=NBAωe_0 = NBA\omega as the peak (maximum) emf: e=e0sin⁡(ωt)e = e_0\sin(\omega t) This shows the emf varies sinusoidally with time, going through one full cycle each time the coil completes one rotation.
  3. Step-down transformer: …

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