An X-ray tube is operated at an accelerating voltage of 40 kV. Calculate the minimum wavelength of the continu

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Using $\lambda_{\min}=\dfrac{hc}{eV}$ (Exercise 5) with $V=40\times10^3\ \text{V}$ :

hc = 6.63\times10^{-34}\times3\times10^8 = 1.989\times10^{-25}\ \text{J}\cdot\text{m}

eV = 1.6\times10^{-19}\times40\,000 = 6.4\times10^{-15}\ \text{J}

$\lambda_{\min} = \frac{1.989\times10^{-25}}{6.4\times10^{-15}} \approx 3.11\times10^{-11}\ \text{m} = 31.1\ \text{pm}$ …

Q.An X-ray tube is operated at an accelerating voltage of $40$ kV. Calculate the minimum wavelength of the continuous X-ray spectrum it produces.