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Numerical · Q26

Q.Using Moseley's law in the form ν=34cR(Z−1)2\nu = \dfrac{3}{4}cR(Z-1)^2 for the KαK_\alpha line, calculate the wavelength of the KαK_\alpha X-ray line emitted by a copper target (Z=29Z=29).

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Using ν=34cR(Z−1)2\nu = \dfrac{3}{4}cR(Z-1)^2 with c=3×108 m/sc=3\times10^8\ \text{m/s}, R=1.097×107 m−1R=1.097\times10^7\ \text{m}^{-1}, Z=29Z=29 (copper):

cR=3×108×1.097×107=3.291×1015 HzcR = 3\times10^8\times1.097\times10^7 = 3.291\times10^{15}\ \text{Hz}

34cR=2.468×1015 Hz,(Z−1)2=(28)2=784\frac{3}{4}cR = 2.468\times10^{15}\ \text{Hz}, \qquad (Z-1)^2=(28)^2=784

ν=2.468×1015×784≈1.935×1018 Hz\nu = 2.468\times10^{15}\times784 \approx 1.935\times10^{18}\ \text{Hz}

λ=cν=3×1081.935×1018≈1.55×10−10 m=155 pm\lambda = \frac{c}{\nu} = \frac{3\times10^8}{1.935\times10^{18}} \approx 1.55\times10^{-10}\ \text{m} = 155\ \text{pm} …

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